Bits in an Integer, and Hex Conversions

CS 301 Lecture, Dr. Lawlor

Storage Sizes

Eight bits make a "byte" (note: it's pronounced exactly like "bite", but always spelled with a 'y'), although in some rare networking manuals (and in French) the same eight bits would be called an "octet" (hard drive sizes are in "Go", Giga-octets, when sold in French).  There are some rarely-used, quasi-joke measurements like a four-bit "nybble", but these are quite rare, and basically just jokes.   In DOS and Windows programming, 16 bits is a "WORD", 32 bits is a "DWORD" (double word), and 64 bits is a "QWORD"; but in other contexts "word" means the machine's natural binary processing size, which ranges from 32 to 64 bits nowadays.  "word" should now be considered ambiguous.  Giving an actual bit count is the best approach ("The file begins with a 32-bit binary integer describing...").

Object
Unsigned Range Signed Range
Bits
Hex Digits
(4 bits)

Bytes
(8 bits)
Octal Digits
(3 bits)

Bit
0..1
-1..0
1
less than 1
less than 1less than 1
Byte, "char"
255
-128 .. 127
8
2
1
two and two thirds
"short" (or Windows WORD)
65535
-32768 .. +32767
16
4
2
five and one third
"int" (Windows DWORD)
>4 billion
-2G .. +2G
32
8
4
ten and two thirds
"long" (or "long long" on some machines)
>16 quadrillion
-8Q .. +8Q
64
16
8
twenty-one and one-third

You can determine the usable range of a value by experimentally measure the overflow point, for example with code like this:
int value=1; /* value to test, starts at first (lowest) bit */
for (int bit=0;bit<100;bit++) {
std::cout<<"at bit "<<bit<<" the value is "<<value<<"\n";
value=value+value; /* moves over by one bit (value=value<<1 would work too) */
}
return 0;

(Try this in NetRun now!)

Base Conversion

It's pretty easy to write code to extract the bits of an integer, and print them out.
/* Print the low 32 bits of this number */
void print_binary(int v)
{
for (int bit=31;bit>=0;bit--) {
if ((v&(1<<bit))!=0) {
std::cout<<"1";
} else {
std::cout<<"0";
}
}
std::cout<<" binary\n";
}

int foo(void) {
print_binary(6);
return 0;
}
(executable NetRun link)

It's also pretty easy to stick together a set of bits (say, in an array) into an integer:
const int bits[]={1,1,0};
int nbits=sizeof(bits)/sizeof(bits[0]); /*<- funky trick to find size of static array!*/
int value=0;
for (int bit=0;bit<nbits;bit++) {
if (bits[nbits-1-bit]) /*<- gotta index the bit array starting at the end */
value = value | (1<<bit);
}
return value;

(Try this in NetRun now!)

Or you can do the same binary-to-integer conversion using digits from cin:

void print_binary(int v) {
for (int i=0;i<32;i++)
{
int mask=1<<(32-1-i);
if ((v&mask)==0) std::cout<<"0";
else std::cout<<"1";
}
std::cout<<endl;
}
int read_binary(void) {
int v=0;
while (std::cin) {
char c='?';
std::cin>>c;
//std::cout<<"I just read the character '"<<c<<"'."<<endl;
if (c=='0') {
/* zero digit in that place */
v=v<<1;
} else if (c=='1') {
/* one digit in that place */
v=(v<<1)+1;
}
else {
break;
}
}
return v;
}

int foo(void) {
return read_binary();
}

(Try this in NetRun now!)

What's the deal with all this hex?

Humans have used the "place/value" number system for a long time--the Sumerians used base-60 in 4000BC! (Base-60 still shows up in our measurement of time and angles: hours have 60 minutes, which have 60 seconds, degrees also have seconds, and the circle is divided into six sections of 60 degrees each.  The Maya used base 20.  The world standard, though, is now base 10 using Arabic numerals.  For example, I'm 34 = 3 * 10 + 4 years old.

But every computer built today uses binary--1's and 0's--to do its work.  The reason is electrical--0 is no voltage, 1 is voltage.  Having just two states makes it easy to build cheap and reliable circuits; for example, a transistor will threshold the input value and either conduct or not conduct.  A single zero or one is called a "bit". 

OK, so we got 1's and 0's: how to we build bigger numbers?  The modern standard method is using "binary", which is just the place-value system using base 2.  In binary, 1 means 1; 10 (base 2) means 2 (base 10); 100 (base 2) means 4 (base 10); 1000 (base 4) means 8 (base 10);  10000 (base 2) means 16 (base 10); and so on.  Every machine produced today supports direct binary arithmetic. Sadly, for a human writing or reading binary is really painful and error-prone for large numbers.  For example, one million is 11110100001001000000 (base 2), which is painful to write or read.  So instead, we often use a larger base. 

Back in the 1970's, it was pretty common to use octal (base 8), but the modern standard is hexadecimal--base 16.  Base 16's gotta use 16 different digits, and there are only 10 arabic numerals, so we use normal alphabet letters for the remaining digits.  For example, 15 (base 10) is just F (base 16); an one million in hex is F4240 (base 16).  You've got to be careful about the base, though--the string "11" would be interpreted as having the value 1*2+1=3 if it was base 2, the usual 1*10+1=11 if it was base 10, or 1*16+1=17 in base 16!

Place/bit Numberi
...
4
3
2
1
0
Decimal: Base-10
10i
...
10000
1000
100
10
1
Binary: Base-2
2i ...
16 = 24
8 = 23
4 = 22
2
1
Octal: Base-8
8i
...
4096=84 512=83 64=82 8
1
Hex: Base-16
16i ...
65536 = 2
4096 = 163 256 = 162
16
1
Base-n
ni ...
n4
n3 n2 n
1 = n0

Number bases used throughout time:
Decimal
Hex Binary
0
0 0
1
1 1
2
2 10
3
3 11
4
4 100
5
5 101
6
6 110
7
7 111
8
8 1000
9
9 1001
10
A 1010
11
B 1011
12
C 1100
13
D 1101
14
E 1110
15
F 1111
16
10
10000
Hexadecimal-to-decimal and binary table.

Note that a single digit in base 16 corresponds to exactly 4 bits, since 16=2*2*2*2.  This means it's easy to convert from a binary number to a hex number: take groups of 4 bits and convert to a hex digit--or back again: take each hex digit and expand out to the 4 bits it represents.  For example, 0xF036 is, in binary, 1111000000110100, because you can match up the place-values like this:
Hex Place-Value
163
162
16
1=160
Hex Digit
F
0
3
6
Binary Digit
1
1
1
1
0
0
0
0
0
0
1
1
0
1
1
0
Binary Place-Value
215
214
213
212
211
210
29
28
27
26
25
24
23
22
21
20
Converting 0xF036 (hex) to 1111000000110110 (binary)

Hex really is the only true universal in assembly and disassembly.  For example, here's some random disassembled code (produced using "objdump -drC -M intel /bin/ls" on a Linux machine):
 804a516:       80 fa 3f                cmp    dl,0x3f
804a519: 0f 84 7c 01 00 00 je 804a69b <exit@plt+0xc2b>
Note that every single number is listed in hex--the addresses, on the left; the machine code, in the middle; and the constants in the assembly, on the right.  A binary file display tool is called a "hex dump".  A binary file editor is called a "hex editor".  That's how common hex is, so for the rest of the class to make sense, you've gotta learn it!

Hex & Bitwise Operations

Remember that every hex digit represents four bits.  So if you shift a hex constant by four bits, it shifts by one entire hex digit:
    0xf0d<<4 == 0xf0d0
    0xf0d>>4 == 0xf0

Bitwise operators make perfect sense working with hex digits, because they operate on the underlying bits of those digits:
    0xff0 & 0x0ff == 0x0f0
    0xff0 | 0x0ff == 0xfff
    0xff0 ^ 0x0ff == 0xf0f

You can use these bitwise operators to peel off the hex digits of a number, to print out stuff in hex:
int v=1024+15;
for (int digit=7;digit>=0;digit--) {
char *digitTable="0123456789abcdef";
int d=(v>>(digit*4))&0xF;
std::cout<<digitTable[d];
}
std::cout<<std::endl;
return v;

(Try this in NetRun now!)

Arithmetic In Binary, and Signed Numbers

We can do arithmetic in binary or hex by hand just like we do in decimal.  To add, line up the digits, add corresponding digits, and if the per-digit sum is greater than the base, carry to the next digit.  Easy, right?  To subtract, do the exact same thing, but "borrow" from the next digit if the per-digit difference is less than 0.

For example, in binary 01+01=10 because the first digit overflows, and the extra "1" is carried to the next digit.  Similarly, 1111+1=10000 because all the digits overflow in sequence.  In general, adding a "1" will cause carries to ripple up through ones, flipping them to zeros, until it finally reaches a zero, which it will flip to a one.

Addition in hex is exactly the same--it's a bit tricker to add the larger digits involved, but carries work exactly the same.  So  0x8+0x8=0x10, and 0xffff+0x1=0x10000.

Subtraction in binary seems really bizarre until you remember than 10-1=1 in binary--that is, "1" is the one-less-than-zero digit in binary; just like "9" is the corresponding one-below-zero digit in decimal.  So when you have to borrow, you just flip the zeros to ones until you hit a one. 

Subtraction actually shows you how to represent negative numbers in binary.  Consider -1==0-1: you just keep on flipping zeros to ones forever, "borrowing" against the future that never comes (just like the US banking system!).  So -1 is represented (in principle) by an infinite number of ones, just like +1 is represented (in principle) by an infinite number of zeros followed by a one.  In practice, we only store a finite number (usually 32 or 64) of bits, so on a 32-bit machine we define 32 ones as -1.  The highest bit, then, can be thought of as a "sign bit"--negative numbers have that bit set, positive numbers have that bit clear.  Suprisingly, it make sense to think of the sign bit in digit n as having value -2n, instead of value 2n for unsigned numbers.  What's weirder is that addition and subtraction are exactly the same for signed or unsigned numbers--try it!  (All other operations are different, though: comparison, multiplication, division, etc.)

Signed versus unsigned numbers are clearer if you draw them out for a 3-bit machine:
Bit Pattern
Unsigned Value
Signed Value
000
0
0
001
1
1
010
2
2
011
3
3
100
4
-4
101
5
-3
110
6
-2
111
7
-1

Note that everything but Java supports "signed" as well as "unsigned" integers explicitly.  In C/C++/C#, typecasting to an unsigned value does nothing to the bits, and is hence a zero-clock operation.  One way to speed up a "zero to n" bounds test on a signed value is to turn it into an unsigned value and just compare against n--that is, "if ((x>=0)&&(x<n)) ..." is the same as "if (((unsigned int)x)<n) ..." do exactly the same thing, because negative signed x's will turn into really huge unsigned x's!

In hex, -1 (in binary, all ones) is written in hex as 0xFFffFFff (on a 32-bit machine).

Another way to think about -1 is that it's like "99999" on a car's odometer--if you drive one more mile, you'll be at "00000", so you're really at mile -1!